physics
posted by Anonymous on .
An automobile starts from rest and accelerates to a final velocity in two stages along a straight road. Each stage occupies the same amount of time. In stage 1, the magnitude of the car's acceleration is 3.12 m/s2. The magnitude of the car's velocity at the end of stage 2 is 3.20 times greater than it is at the end of stage 1. Calculate the magnitude of the acceleration in stage 2.

let vf=velociyt end of stage1
the velociyt at end of stage2 is 3.2vf
Stage 1
vf=3.12*time
stage 2
3.2vf=vf+a*time
first equation: time=vf/3.12
then 3.2Vf=vf+a*vf/3.12
a= (3.21)3.12 check my math.