posted by Anonymous on .
An automobile starts from rest and accelerates to a final velocity in two stages along a straight road. Each stage occupies the same amount of time. In stage 1, the magnitude of the car's acceleration is 3.12 m/s2. The magnitude of the car's velocity at the end of stage 2 is 3.20 times greater than it is at the end of stage 1. Calculate the magnitude of the acceleration in stage 2.
let vf=velociyt end of stage1
the velociyt at end of stage2 is 3.2vf
first equation: time=vf/3.12
a= (3.2-1)3.12 check my math.