Posted by Kathy on .
write the general form of
f(x)=4(x1)^8
(x1) (x1)=
4(x^2x+1)8
4x^2x8

algebra 2 
Steve,
Use a number with exponents.
4(x1)^2  8
4(x^22x+1)8
4x^28x+48
4x^28x4
You must multiply the 4 by each term in the parentheses, not just the first one.
4(2+6) = 4*2 + 4*6 = 8+24 = 32
NOT
4(2+6) = 4*2+6 = 8+6 = 14
after all, 2+6=8, and 4*8 = 32 
algebra 2 
Reiny,
f(x) = 4(x1)^2  8
= 4(x^2  2x + 1)  8
= 4x^2  8x + 4  8
= 4x^2  8x  4