Posted by **Neha** on Wednesday, September 3, 2014 at 6:35pm.

An airplane has an airspeed of 770 kilometers per hour at a bearing of N 48 degrees E. If the wind velocity is 28 kilometers per hour from the west, find the angle representing the bearing for

the ground speed?

I found Rx and Ry which are 543.23 and 572.22 respectively. To find the angle I took tan^-1 of 572.22/543.23 and got 46. 489 for the angle, but the answer is wrong. R=789 and I got that right so I don't understand why the angle is incorrect.

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