How much heat must be removed from a 240 g block of copper to lower its temperature from 150°C to 18°C? The specific heat capacity of copper is 0.093 cal/g·C°.
To calculate the amount of heat that must be removed from the copper block, we can use the formula:
Q = m * c * ΔT
where Q is the amount of heat, m is the mass of the object, c is the specific heat capacity of the substance, and ΔT is the change in temperature.
In this case:
m = 240 g (the given mass of the copper block)
c = 0.093 cal/g·C° (the specific heat capacity of copper)
ΔT = 150°C - 18°C = 132°C (the change in temperature)
Now we can plug in these values to calculate Q:
Q = 240 g * 0.093 cal/g·C° * 132°C
Calculating this:
Q ≈ 2901.6 cal
Therefore, approximately 2901.6 calories of heat must be removed from the 240 g block of copper to lower its temperature from 150°C to 18°C.