Olivia's chessboard is 11 sq centimeters. A chessboard. Has 8 sq on each side. To the nearest tenth what is the width of the chessboard
Doesn't matter how many squares there are. The board is square, so each side is
√11 = 3.3 cm
must be a travel set.
I suspect a typo.
To find the width of the chessboard, we need to divide the total area by the number of squares on one side.
Given that the chessboard has 8 squares on each side, the total number of squares is 8 * 8 = 64 squares.
Since the total area is 11 square centimeters, we can divide 11 by 64 to find the area of each square: 11 / 64 = 0.1719 square centimeters.
Now, to find the width of the chessboard, we can take the square root of the area of each square because the squares on the chessboard are usually square shaped.
Taking the square root of 0.1719, we get approximately 0.414 centimeters.
Therefore, the width of the chessboard, to the nearest tenth, is 0.4 centimeters.