Posted by DUE AT MIDNIGHT PLEASE HELP!!! on .
A trough is 2 feet long and 1 foot high. The vertical cross-section of the trough parallel to an end is shaped like the graph of y=x10 from x=−1 to x=1. The trough is full of water. Find the amount of work required to empty the trough by pumping the water over the top. Note: The weight of water is 62 pounds per cubic foot. Your answer must include the correct units. (You may enter lbf or lb*ft for ft-lb.)
I got 5194.10 and 81.158 and both were wrong, I am so stuck I have been working on this question for over an hour!!!! and the assignment is due at midnight, please help!!!!
I do not know what
y = x10 means
Whatever the function is you must find the distance from the top (y =1) down to the centroid, which is the center of mass of the water. That is the distance you have to lift the water, call it h.
Then find the volume V , the area times 2 feet.
work = 62 lbs/ft^2 * volume in ft^3 * h
typo, 62 lbs/ft^3