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March 2, 2015

March 2, 2015

Posted by **kenzie** on Tuesday, September 2, 2014 at 4:25pm.

I don't know what I am doing wrong on this problem. So I used the equation y(t)= y0 + v0t + ((1/2)qEt^2)/m

I rearranged it to solve for E in terms of t and got E= 2.733e-5/t then I plugged in the t I got from finding x=vxt=1.5cm

My answer came out to be 3.44e3 N/C

- phys urgent! -
**Damon**, Tuesday, September 2, 2014 at 4:59pmI do not have time to run your numbers but your approach is correct.

constant Vx = 2.4*10^6 cos 38

so t = .015 /Vx

Vyi = 2.4*10^6 sin 38

y = Vyi t -(1/2)(qE/m) t^2 = 0 at x axis

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