posted by k on .
Suppose you have two 100-mL graduated cylinders. In each cylinder there is 40.0mL of water. You also have two cubes: one is lead(11.3g/ml), and the other is aluminum(2.70g/ml) Each cube measures 2.0cm on each side. After you carefully lower each cube into the water of the cylinder?
They both displace the same volume and mass of water so both weights are reduced by density of water * g * volume of cube
You asked this same question last night (actually you finished the question last night). Bob Pursely answered the question, you questioned his answer and I followed up with the same answer Damon has given you here. You may as well accept the answer because it's right; both cubes, if they have the same volume, displace the same amount of water. The old water volume is 40 cc, you displace 8 cc so the new water volume is 48 cc for BOTH. It makes no difference what the identity is. You can have 8 cc lead, 8 cc aluminum, or 8 cc of feathers and 40 + 8 = 48. Period.