If joe stands. 25ft away from a 40ft buliding how long would a ladder have to be to reach from the ground where joe is standing to the top of the building
Use the Pythagorean Theorem as I showed you before. This time solve for c.
http://www.jiskha.com/display.cgi?id=1409358389
I did
A^2+b^2=c^2
40^2+25^2=C^2
1,600+625=C^2
Then i got 2,225=c^2
And i don't think that is the answer
Ms.sue
You're right as far as you went.
2,225 = c^2
The square root of 2,225 is 47.17 feet
c^2 = 40^2 + 25^2 = 2225
c = √2225
= appr 47.17 ft
To determine the length of the ladder needed to reach from the ground to the top of the building, we can use the Pythagorean theorem, which states that in a right-angled triangle, the square of the length of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the other two sides.
In this case, we have a right-angled triangle with one side measuring 25 ft and the other side measuring 40 ft (the height of the building). Let's assume the ladder (hypotenuse) has a length of "x" ft. So, we can set up the equation:
x^2 = 25^2 + 40^2
Simplifying the equation:
x^2 = 625 + 1600
x^2 = 2225
To find the value of "x," we need to take the square root of both sides:
x = √2225
Using a calculator, the square root of 2225 is approximately 47.16 ft.
Therefore, the ladder would need to be approximately 47.16 ft long to reach from the ground where Joe is standing to the top of the building.