Friday

November 28, 2014

November 28, 2014

Posted by **roger** on Friday, August 29, 2014 at 2:04pm.

- maths -
**Steve**, Friday, August 29, 2014 at 2:17pmsince distance = speed*time, if the still-water speeds of the men are a and b,

(a-.5)(5) = 10

(b+.5)(3) = 10

5a - 5/2 = 10

3b + 3/2 = 10

b-a = (10 - 3/2)/3 - (10+5/2)/5 = 1/3

- maths -
**roger**, Friday, August 29, 2014 at 3:55pmSir, I am also getting this as the answer. but the options given are :-

a). 2.45

b). 2.3

c). 1.33

d). 1.56

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