A hollow sphere us charged to 14uc .Find the potential(a) at its surface (b) inside the sphere (c) at a distance of 0.2m from the surface.The radius of sphere is 0.3 m

To solve this problem, we need to use the concept of electrostatics, specifically Coulomb's law and the formula for electric potential.

Let's go step by step to find the potential at different points.

(a) To find the potential at the surface of the hollow sphere, we can use the formula for electric potential due to a point charge:

V = k * (q / r)

Where:
V = Potential
k = Coulomb's constant (8.99 x 10^9 N m^2/C^2)
q = Charge
r = Distance from the center of the charge

Since the sphere is hollow, the entire charge is present on its surface. So, q = 14 μC.

And the radius of the sphere is given as 0.3 m. So, r = 0.3 m.

Plug in these values into the formula:

V = (8.99 × 10^9 N m^2/C^2) * (14 × 10^-6 C) / 0.3 m

Simplify the calculation to find the potential at the surface.

(b) Inside the sphere, the electric potential is constant and equal to the potential at the surface. Therefore, the potential inside the sphere is the same as the potential at the surface that we calculated in part (a).

(c) To find the potential at a distance of 0.2 m from the surface, we need to consider the potential due to both the sphere and the remaining charge outside it.

Assuming all of the remaining charge is uniformly distributed on the surface of the sphere:

V = k * (q / r)

Here, q is the remaining charge and r is the distance from the center of charge. The remaining charge is given by:

Remaining charge = Total charge - Charge on the sphere's surface
= 14 μC - (charge density * surface area of sphere)

To find the charge density and surface area of the sphere, we need the radius of the hole, the inner radius, and the outer radius of the sphere. However, those values are not provided in the question. Please provide those values so we can calculate the remaining charge, and subsequently, the potential at a distance of 0.2 m from the surface.