Friday

December 19, 2014

December 19, 2014

Posted by **nithin** on Friday, August 29, 2014 at 10:05am.

If the root of the equation x²-8x+m=0 exceeds the other by 4 then the value of m is

- math -
**Steve**, Friday, August 29, 2014 at 11:10amthe roots are

x = (8±√(64-4m))/2 = 4±√(16-m)

So, we have

4+√(16-m) = 4-√(16-m) + 4

2√(16-m) = 4

√(16-m) = 2

16-m = 4

m = 12

So, the function is

x^2-8x+12, and the roots are 2 and 6

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