Chemistry
posted by Danielle on .
The level of water in a rectangular swimming pool needs to be lowered 4.00 inches. If the pool is 36.50 ft long and 15.00 ft wide, and the water is siphoned out at a rate of 5.0 gal/min, how long will the siphoning take?
1 ft^3 = 7.48 gal.

volum of water removed: 1/3 ft x 36.5ft x 15ft.
calculate that volume
Now convert ft^3 to gal. there are 7.48 gallons per ft^3
Now,
time=volumeinGallons/ratepump