The level of water in a rectangular swimming pool needs to be lowered 4.00 inches. If the pool is 36.50 ft long and 15.00 ft wide, and the water is siphoned out at a rate of 5.0 gal/min, how long will the siphoning take?

1 ft^3 = 7.48 gal.

volum of water removed: 1/3 ft x 36.5ft x 15ft.

calculate that volume

Now convert ft^3 to gal. there are 7.48 gallons per ft^3

Now,

time=volumeinGallons/ratepump

Well, if you're trying to lower the water level in a swimming pool, I suggest hiring a bunch of thirsty elephants. They can drain it in no time!

But if you'd rather go with the siphoning method, here's the mathy answer. To find out how long it will take, we need to convert the pool's dimensions into volume.

The volume of the pool is equal to its length times its width times the change in height.

Let's first convert the change in height from inches to feet: 4.00 inches = 4.00/12 ft = 0.33 ft.

So, the volume of water we need to remove is 36.50 ft x 15.00 ft x 0.33 ft = 181.35 ft^3.

Now, we can convert this volume into gallons using the conversion factor you provided: 1 ft^3 = 7.48 gal.

181.35 ft^3 x 7.48 gal/ft^3 = 1,355.32 gallons.

Since the water is siphoned out at a rate of 5.0 gal/min, we can divide the volume by the rate to find the time it will take:

1,355.32 gallons / 5.0 gal/min = 271.06 minutes.

So, it will take approximately 271.06 minutes to lower the water level in the pool. Just make sure you have some good entertainment to keep you busy while you wait!

To find out how long the siphoning will take, we need to determine the volume of water that needs to be siphoned out of the pool and then divide it by the flow rate of the siphon.

Step 1: Convert the dimensions of the pool to inches:
Length of the pool = 36.50 ft * 12 inches/ft = 438 inches
Width of the pool = 15.00 ft * 12 inches/ft = 180 inches

Step 2: Calculate the volume of water to be siphoned out:
The volume of water in the pool can be calculated by multiplying the length, width, and depth. Since the depth needs to be lowered by 4.00 inches, we subtract 4.00 inches from the current depth of the pool.
Depth of the pool = 4.00 inches
Volume = Length * Width * Depth
Volume = 438 inches * 180 inches * 4.00 inches = 315,360 cubic inches

Step 3: Convert the volume to gallons:
1 ft^3 = 7.48 gallons
1 cubic inch = 1/12^3 ft^3 = 0.0005787 ft^3
Volume in cubic feet = 315,360 cubic inches * 0.0005787 ft^3/inch^3 = 182.22 ft^3
Volume in gallons = 182.22 ft^3 * 7.48 gallons/ft^3 = 1360.3 gallons

Step 4: Calculate the time it takes to siphon the water out:
Rate of siphoning = 5.0 gallons/minute
Time = Volume / Rate
Time = 1360.3 gallons / 5.0 gallons/minute = 272.06 minutes

Therefore, it will take approximately 272.06 minutes to siphon the water out of the pool.

To find out how long the siphoning will take, we need to calculate the volume of water that needs to be drained from the pool and then divide it by the rate at which water is being siphoned.

The first step is to calculate the volume of water that needs to be drained. We are given that the pool needs to be lowered by 4.00 inches, so we need to find the volume of the rectangular portion of the pool that is 4.00 inches deep.

Given:
Length of the pool (L) = 36.50 ft
Width of the pool (W) = 15.00 ft
Depth to be lowered (D) = 4.00 inches

To calculate the volume, we convert the dimensions to feet:
Length (L) = 36.50 ft
Width (W) = 15.00 ft
Depth (D) = 4.00 inches = 4.00/12 = 0.33 ft (converting inches to feet)

Now we can calculate the volume of water that needs to be drained from the pool:
Volume = Length x Width x Depth
Volume = 36.50 ft x 15.00 ft x 0.33 ft

Next, we need to convert the volume from cubic feet (ft^3) to gallons (gal) using the conversion factor:
1 ft^3 = 7.48 gal

So, the volume of water to be drained in gallons (V) is:
V = (36.50 ft x 15.00 ft x 0.33 ft) x 7.48 gal/ft^3

Now, we can calculate the time required for siphoning. We divide the volume by the rate at which water is being siphoned, which is given as 5.0 gal/min:
Time = Volume / Siphoning rate
Time = V / 5.0 gal/min

Plugging in the values, we get:
Time = (36.50 ft x 15.00 ft x 0.33 ft x 7.48 gal/ft^3) / 5.0 gal/min

By multiplying the values and canceling out units, we can calculate the time it will take to siphon the water from the pool.