the ratio of of the number of adults to the number of students at the prom has to be 1:10. Last year there were 477 more students than adults at the prom. If the school is expecting the same attendance this year how many adults have to attend prom?
hey i'm in 6th grade and this is for homework today and i really need an answer
hello my fans this question is too hard for me but i can answer another one🙂🙂😘
I need the answer because it’s 11pm and I forgot to do my home work :c
I need the answer because it’s 11pm and I forgot to do my home work :c
I’ll do it myself
477/10 = ? (round to whole number)
To solve this problem, we can start by setting up a system of equations based on the given information.
Let's assume the number of adults at the prom is "A" and the number of students is "S".
According to the given ratio, the ratio of adults to students is 1:10, which can be written as:
A/S = 1/10
We are also given that last year there were 477 more students than adults at the prom. Mathematically, this can be represented as:
S = A + 477
To find out how many adults need to attend the prom this year, we need to solve these equations simultaneously.
Since we have an equation for "S" in terms of "A", we can substitute this value into the first equation:
A/(A + 477) = 1/10
Now, we can solve this equation to find the value of "A".
To do this, we can cross-multiply:
10A = A + 477
Expanding the equation:
10A - A = 477
9A = 477
Now, divide both sides of the equation by 9:
A = 477 / 9
A = 53
Hence, there need to be 53 adults to attend the prom this year in order to maintain the ratio of 1:10 between adults and students.