Two boats leave a dock at the same time, one goes eastward at 10miles per hour and the other goes north at 24miles per hour how miles apart are both boats after 3hours
one East has went 30mi
one N has went 72 miles
right triangle
distance=sqrt(30^2+72^2)
To find the distance between the two boats, we can use the Pythagorean theorem. Let's consider the eastward boat as moving along the x-axis and the northward boat as moving along the y-axis.
The eastward boat travels at a speed of 10 miles per hour for 3 hours. Therefore, its total distance along the x-axis would be 10 miles/hour * 3 hours = 30 miles.
The northward boat travels at a speed of 24 miles per hour for 3 hours. Thus, its total distance along the y-axis would be 24 miles/hour * 3 hours = 72 miles.
Now, using the Pythagorean theorem, we can calculate the distance between the two boats:
Distance = √((30 miles)^2 + (72 miles)^2)
= √(900 miles^2 + 5184 miles^2)
= √(6084 miles^2)
≈ 78 miles
Therefore, the two boats are approximately 78 miles apart after 3 hours.