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Can a/b and (a+b)/b ever form a proportion? Why or why not?

  • MA - ,

    well, let's try it ...

    a/b = (a+b)/b
    times b, if b ≠0

    a = a+b
    then b = 0
    but now we have a contraction, so .....


    cross - multiply
    ab = ab + b^2
    b^2 = 0
    b = 0 , but that would make a/b undefined,

    so what do you think?

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