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Math

posted by on .

x^(log10x)=100

I'm not sure how to do this at all...

  • Math - ,

    I will assume you meant ...

    x^(log10 x = 100

    then by definition:

    logx 100 = log10x
    changing to a common base of the log ...

    log10 100/logx = logx/log1010
    2/log10x = log10 x/1
    (log10 x)^2 = 2
    log10 x =√2

    using my calculator
    x = appr 25.9546 or x = appr .03853

    (both answers can be verified)

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