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February 28, 2015

February 28, 2015

Posted by **Tyler** on Monday, August 25, 2014 at 9:27pm.

I'm not sure how to do this at all...

- Math -
**Reiny**, Monday, August 25, 2014 at 10:02pmI will assume you meant ...

x^(log_{10}x = 100

then by definition:

log_{x}100 = log_{10}x

changing to a common base of the log ...

log_{10}100/log_{x}= log_{x}/log_{10}10

2/log_{10}x = log_{10}x/1

(log_{10}x)^2 = 2

log_{10}x =√2

using my calculator

x = appr 25.9546 or x = appr .03853

(both answers can be verified)

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