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October 1, 2014

October 1, 2014

Posted by **Lorine** on Monday, August 25, 2014 at 7:58pm.

4 sec^7 (πt − 6)?

- Calculus-Math -
**Damon**, Monday, August 25, 2014 at 8:09pmwell, we know we keep the 4 :)

Let z = 4(sec u)^7 and u = pi t - 6

then

dz/du = 4 * 7 (sec u)^6 d sec u/du

= 28 (sec u)^6 (sec u )(tan u)

= 28 sec^7 u tan u

dz/dt = dz/du * du/dt = dz/du * pi

so

dz/dt = 28 pi sec^7(pi t-6)tan(pi t-6)

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