A body travels from rest with acceleration 8m/s(squared)Find its velocity when it has covered a distance of 100 meter?
vf^2=vi^2+2*acceleration*distance
THE ANSWER IS 40MS
0.8 m/s^2
To find the velocity of a body that travels from rest with a given acceleration after covering a certain distance, we can use the equations of linear motion.
The equation that relates distance (d), initial velocity (u), acceleration (a), and final velocity (v) is:
v^2 = u^2 + 2ad
In this case, the body starts from rest, so the initial velocity (u) is 0 m/s. The acceleration (a) is given as 8 m/s^2, and the distance (d) is 100 meters.
Substituting these values into the equation:
v^2 = 0^2 + 2(8)(100)
v^2 = 1600
v = √1600
v = 40 m/s
Therefore, the velocity of the body when it has covered a distance of 100 meters is 40 m/s.