a number consists of two digits whose sum is 8.if 8 is added to the number its digits are reversed.find the number?
Do you mean 18 is added? If so:
17,26,35.
35 + 18 = 53
So the number is 35.
A number consist Of two digits whose sum is 8.if 8 is added to the number it's digits are reversed. Find the number.
To solve this problem, we can use algebraic equations.
Let's assume the number has two digits: the tens place digit (T) and the units place digit (U).
According to the given information, the sum of the two digits is 8. We can write this as an equation:
T + U = 8 ----(Equation 1)
The second piece of information states that if 8 is added to the number, its digits are reversed. This can be written as another equation:
10U + T + 8 = 10T + U ----(Equation 2)
We can simplify Equation 2 by expanding and rearranging the terms:
9U - 9T = -8
Now, let's solve the system of equations by substituting Equation 1 into Equation 2:
9U - 9(8 - U) = -8
9U - 72 + 9U = -8
18U - 72 = -8
18U = 64
U = 64/18
U ≈ 3.56
Since U represents the units place digit, it cannot be a decimal value. Therefore, we cannot find a whole number solution using this process.
Hence, there is no two-digit number that satisfies the given conditions in this case.