solve using elimination please show how to come up with answer.
6x - 3y = 18
6x + 3y = -12
Please help!!!
Add the two equations.
12x = 6
Solve for x and then insert that value into one of the equation to find y. To check, insert x value into the other equation.
1. x=Y/2+3
2. y= -y/2 - 1/3
To solve the given system of equations using elimination, we need to eliminate one of the variables by adding or subtracting the two equations.
Looking at the given equations:
Equation 1: 6x - 3y = 18
Equation 2: 6x + 3y = -12
We can eliminate the variable "y" by adding the two equations together. When we add the equations, the "y" terms will cancel out, leaving us with an equation in terms of "x" only.
So, let's add the two equations:
(6x - 3y) + (6x + 3y) = 18 + (-12)
When we add the like terms on both sides, the equation becomes:
12x = 6
To isolate "x" and solve for its value, we divide both sides of the equation by 12:
(12x)/12 = 6/12
x = 1/2
Now that we have found the value of "x," we can substitute it back into either of the original equations to find the value of "y."
Let's substitute "x = 1/2" into Equation 1:
6(1/2) - 3y = 18
3 - 3y = 18
-3y = 18 - 3
-3y = 15
To isolate "y" and solve for its value, we divide both sides of the equation by -3:
(-3y)/(-3) = 15/(-3)
y = -5
Therefore, the solution to the given system of equations is x = 1/2 and y = -5.