A roof section of a house is a large triangle. it measures 6.4 meters at the base and is 3.8 meters high. If one liter of paint covers 3 meters square, how many litres are needed to paint this section twice? Answer to the nearest litre.
To find the area of the roof section, we can use the formula for the area of a triangle: Area = (base × height) / 2.
Given that the base of the triangle is 6.4 meters and the height is 3.8 meters, the area of the roof section is:
Area = (6.4 × 3.8) / 2
Area = 24.32 square meters
To find how many liters of paint are needed to cover this area, we divide the area by the coverage rate of the paint:
Coverage rate of paint = 3 square meters per liter
Litre = Area / Coverage rate of paint
Litre = 24.32 / 3
Litre = 8.107
Since we need to paint the section twice, we multiply the required amount of paint by 2:
Total liters needed = 8.107 × 2
Total liters needed = 16.214
Rounding this to the nearest liter, we find that approximately 16 liters of paint are needed to paint this section twice.
To find the area of the roof section, we can use the formula for the area of a triangle: A = (base x height) / 2.
Given that the base of the triangle is 6.4 meters and the height is 3.8 meters, we can substitute these values into the formula:
A = (6.4 x 3.8) / 2
A = 24.32 / 2
A = 12.16 square meters
Now, we know that one liter of paint covers 3 square meters. So, to calculate the number of liters needed to paint the roof section once, we divide the area by 3:
Number of liters for one coat = 12.16 / 3
Number of liters for one coat ≈ 4.053 liters
To paint the section twice, we simply double the amount of paint needed for one coat:
Number of liters for two coats = 4.053 x 2
Number of liters for two coats ≈ 8.106 liters
Therefore, approximately 8 liters of paint are needed to paint this roof section twice, to the nearest liter.
A = 1/2bh
1/3 = x/A
Insert values to solve for A, then x.