The 1.2-Mg helicopter is traveling at a constant speed of 50m/s along the horizontal curved path while banking at ƒÆ = 30∘.


Part A
Determine the force acting normal to the blade, i.e., in the y�Œ direction.

well, the upward component is mg,

so cos30=mg/bladeforce
solve for blade force. This ignores forward directed force against air resistance.

13.5 kN

To determine the force acting normal to the blade, i.e., in the y-direction, we need to consider the two main forces acting on the helicopter: the weight force (mg) and the centripetal force (Fc) due to the curved path.

The weight force (mg) acts vertically downward and can be calculated using the mass (m) of the helicopter and the acceleration due to gravity (g). The weight force is given by the equation:

Weight Force (mg) = mass (m) * acceleration due to gravity (g)

Given that the mass of the helicopter is 1.2 Mg, we need to convert it to kilograms first. 1 Mg is equal to 1000 kg, so 1.2 Mg is equal to 1200 kg.

Weight Force = 1200 kg * 9.8 m/s² (approximate value of acceleration due to gravity)

Next, we need to calculate the centripetal force (Fc) acting towards the center of the curved path. The centripetal force is given by the equation:

Centripetal Force (Fc) = mass (m) * velocity squared (v²) / radius of curvature (R)

Since the helicopter is traveling at a constant speed of 50 m/s along the curved path, the velocity squared (v²) is 50² = 2500 m²/s².

However, we don't have the radius of curvature (R) given in the problem. We need to know the radius of the path to calculate the centripetal force accurately. Without this information, we cannot determine the force acting normal to the blade.

Therefore, without the radius of curvature provided, we cannot calculate the force acting normal to the blade in the y-direction.