If 4 coins are tossed simultaneously, what is the probability of getting exactly 3 tails?
4C3(1/2)^3(1/2)^1
=4(1/16)
=1/4
To find the probability of getting exactly 3 tails when 4 coins are tossed simultaneously, we need to consider the total number of possible outcomes and the number of outcomes that meet the condition of getting exactly 3 tails.
Total number of possible outcomes when tossing 4 coins simultaneously:
When tossing a single coin, there are 2 possible outcomes, either a head (H) or a tail (T). Since there are 4 coins, the total number of possible outcomes is 2 * 2 * 2 * 2 = 2^4 = 16.
Number of outcomes with exactly 3 tails:
To get exactly 3 tails, we need to choose 3 out of 4 coins to show tails, while the remaining coin will show heads. The number of ways to choose the 3 tails from 4 coins can be calculated using combinations. The formula for combinations is nCr, where n is the total number of items and r is the number of items chosen.
The number of ways to choose 3 tails out of 4 coins is given by 4C3, which can be calculated as (4!)/(3!*(4-3)!) = 4.
Therefore, the number of outcomes with exactly 3 tails is 4.
Probability of getting exactly 3 tails:
The probability of an event happening is equal to the number of favorable outcomes divided by the total number of possible outcomes.
In this case, the number of favorable outcomes (getting exactly 3 tails) is 4, and the total number of possible outcomes is 16.
Thus, the probability of getting exactly 3 tails is 4/16 = 1/4 = 0.25, or 25%.
So, the probability of getting exactly 3 tails when 4 coins are tossed simultaneously is 0.25 or 25%.