Tuesday

January 27, 2015

January 27, 2015

Posted by **Gen** on Tuesday, August 19, 2014 at 11:03pm.

Based on data from student_data.xls

This is what I have so far. I don't know what the standard deviation would be

N= [ZS/E]^2

N= [ 2.5758*s/2] ^ 2

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