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Posted by on Monday, August 18, 2014 at 4:09pm.

a particle is projected at an angle of 30 degree to the horizontal.
(a), calculate the time of flight of the particle.
(b) speed of the particle at its maximum height

  • physics - , Monday, August 18, 2014 at 4:30pm

    V defined as speed out of the barrel

    time rising = time falling so find rise time and multiply by 2

    vertical problem:
    Vi = V sin 30 = .5 V

    v = Vi - 9.8 t
    v = 0 at top
    0 = .5 V - 9.8 t
    so
    t = .5 V/9.8
    and 2 t = total time aloft = V/9.8

    at max height there is no vertical velocity v
    so the total velocity is the horizontal velocity which does not change
    so
    u = V cos 30

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