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October 1, 2014

October 1, 2014

Posted by **bassey** on Monday, August 18, 2014 at 4:09pm.

(a), calculate the time of flight of the particle.

(b) speed of the particle at its maximum height

- physics -
**Damon**, Monday, August 18, 2014 at 4:30pmV defined as speed out of the barrel

time rising = time falling so find rise time and multiply by 2

vertical problem:

Vi = V sin 30 = .5 V

v = Vi - 9.8 t

v = 0 at top

0 = .5 V - 9.8 t

so

t = .5 V/9.8

and 2 t = total time aloft = V/9.8

at max height there is no vertical velocity v

so the total velocity is the horizontal velocity which does not change

so

u = V cos 30

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