Geometry
posted by itrixie on .
In a triangle with integer side lengths, one side is three times as long as a second side, and the length of the third side is 15. What is the greatest possible perimeter of the triangle?

One side = L units.
2nd side = 3L units.
3rd side = 15 units.
3L < 15
L < 5
L = 4 = Largest possible integer.
3L = 3*4 = 12.
P = 4 + 12 + 15 = 31 = Max. possible
perimeter. 
for sides a<b<c
cb < a < c+b
So, if 3L is the longest side
15L < 3L < L+15
15 < 4L < 2L+15
L > 3.75
L < 7.5
So, the extreme is 7,15,21 for a perimeter of 43 
thank you