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February 1, 2015

February 1, 2015

Posted by **itrixie** on Friday, August 15, 2014 at 5:28pm.

- Geometry -
**Henry**, Friday, August 15, 2014 at 5:59pmOne side = L units.

2nd side = 3L units.

3rd side = 15 units.

3L < 15

L < 5

L = 4 = Largest possible integer.

3L = 3*4 = 12.

P = 4 + 12 + 15 = 31 = Max. possible

perimeter.

- Geometry -
**Steve**, Friday, August 15, 2014 at 11:37pmfor sides a<b<c

c-b < a < c+b

So, if 3L is the longest side

15-L < 3L < L+15

15 < 4L < 2L+15

L > 3.75

L < 7.5

So, the extreme is 7,15,21 for a perimeter of 43

- Geometry -
**itrixie**, Saturday, August 16, 2014 at 4:05pmthank you

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