Posted by Faiz on Friday, August 15, 2014 at 2:30pm.
The speed of the train is reduced from 36 km per hour to 9 km per hour whilst it travels a distance of 150 metres,if the retardation be uniform,find how much further it will travel before coming to rest

Physics  Henry, Friday, August 15, 2014 at 4:56pm
Vo = 36km/h = 36,000m/3600s = 10 m/s.
V = 9km/h = 9000m/3600s = 2.5 m/s.
a = (V^2Vo^2)/2d
a = (2.5^210^2)/300 = 0.3125 m/s^2.
d = (V^2Vo^2)/2a
d = (02.5^2)/0.6250 = 10 m. Further.

Physics  Henry, Thursday, October 30, 2014 at 10:09pm
Or:
d = (10^2)/0.6250 = 160 m.
160  150 = 10 m. Further.
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