Posted by **Adam** on Friday, August 15, 2014 at 8:57am.

If a bicycle wheel has traveled f/π feet after n complete revolutions, what is the length in feet of the diameter of the bicycle wheel?

A. f/nπ^2

B. π^2/fn

C. nf/π^2

D. nf/π^2

E. f/n

- math -
**Reiny**, Friday, August 15, 2014 at 9:01am
n rotations = f/π ft

1 rotation = fπ/n ft

2πr = fπ/n

r = f/(2n) ft

diameter = 2r = f/n ft

- math -
**Adam**, Friday, August 15, 2014 at 9:06am
thanks reiny

- math -
**Mr. Fourth**, Saturday, August 8, 2015 at 10:16am
(F/pi) feet......in N rotation

?.............in 1 rotation

(F/ pi × N)feet

C= 2pi r

(F/ pi × N) = 2pi r

r = ( F/ 2(pi^2)N)

Answer....Dia = F/(pi N^2)

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