A bell rings every 2 seconds, and a bird chirps every 3 seconds. If the ring and the chirp occur together right now, they will occur together in

A. 40 seconds
B. 41 seconds
C. 42 seconds
D. 43 seconds

As Reiny pointed out, the rings and chirps will occur at the same time every 6 seconds, or at

6, 12, 18, 24, 30, 36,.... seconds.

So which of the 4 choices will be a moment where the two sounds will occur together?

the answer is c.)42

Since the last of 2 and 3 is 6. You try to find which answer is divisible by 6 which is answer c 42

L c m not last

Well, if the bell rings every 2 seconds and the bird chirps every 3 seconds, we have to find the least common multiple (LCM) of 2 and 3 in order to determine when they will occur together again. The LCM of 2 and 3 is 6. So, they will occur together every 6 seconds.

But wait, we need to find out when they will occur together starting from now. Since they are occurring together now, we just need to find the next multiple of 6 after this moment. So, the answer is 6 seconds from now, which is option C.

I hope that chirped... I mean, helped!

To find out when the bell ring and the bird chirp will occur together again, we need to find the least common multiple (LCM) of 2 and 3. The LCM is the smallest multiple that both numbers share.

To find the LCM of 2 and 3, we can list the multiples of each number until we find a common multiple:

Multiples of 2: 2, 4, 6, 8, 10, 12, 14, 16, 18, 20, 22, 24, 26, 28, 30, 32, 34, 36, 38, 40, ...

Multiples of 3: 3, 6, 9, 12, 15, 18, 21, 24, 27, 30, 33, 36, 39, 42, ...

From the list, we can see that the first number they have in common is 6. Therefore, the bell ring and the bird chirp will occur together again every 6 seconds.

Since they occur together right now, we need to find out the next time they will occur together, which is 6 seconds from now.

Therefore, the answer is 6 seconds from now, which is option C: 42 seconds.

You keep repeating the same question, which I answered for you, and which does not make sense.