1. How many clories will be needed to change the temperature of 3kg of water from 30degree celsius to 100degree celsius?
please show me how to compute this,
heat=mass*specificheat*deltatTemp
= 3kg* 4.179kJ/kgC*70C= 3*4.179*70 kJ
To calculate the calories needed to change the temperature of water, we can use the specific heat capacity formula:
Q = m * c * ΔT
Where:
Q = amount of heat (in calories)
m = mass of the substance (in kilograms)
c = specific heat capacity of the substance (in calories per gram per degree Celsius)
ΔT = change in temperature (in degrees Celsius)
To solve the problem, we need to convert the given values to the appropriate units.
1 kg = 1000 grams, so 3 kg of water is equal to 3000 grams.
The specific heat capacity of water is approximately 1 calorie per gram per degree Celsius.
Now we can substitute the values into the formula:
Q = 3000 g * 1 cal/g°C * (100°C - 30°C)
Q = 3000 g * 1 cal/g°C * 70°C
Q = 210,000 calories
Therefore, it would take approximately 210,000 calories to change the temperature of 3 kg of water from 30°C to 100°C.