a particle with velocity of 2m/s at t= 0 moves along a straight line with constant acceleration of 0.2m/s2. find the displacement of the particle in 10 seconds
D = Vo*t + 0.5a*t^2
D = 2*10 + 0.5*0.2*10^2 = 30 m.
To find the displacement of the particle in 10 seconds, we can use the equation of motion:
s = ut + (1/2)at^2
Where:
s = displacement
u = initial velocity
t = time
a = acceleration
Given:
u = 2 m/s
a = 0.2 m/s^2
t = 10 seconds
Let's substitute these values into the equation and solve for s:
s = (2)(10) + (1/2)(0.2)(10)^2
s = 20 + (1/2)(0.2)(100)
s = 20 + 10
s = 30 meters
Therefore, the displacement of the particle in 10 seconds is 30 meters.