A sequence of numbers is called a Fibonacci-type sequence if each number (after for the first two) is the sum of the two numbers which precede it. For example, 1, 1, 2, 3, 5, 8 ... is a Fibonacci- type sequence. If 1985, x, y, 200 are four consecutive terms in a Fibonacci-type sequence, then x equals...
I don't know what they want. Please help.
y = 1985 + x
200 = x + y
so
200 = x + (1985+x)
back to you :)
By the way I suspect you mean 2000 not 200
It would help if that last date were odd :)
It is 2000. But thanks!
y = 1985+x
200 = x+y
Eliminate y and we have
1985+x = 200-x
2x = -1785
x = -892.5
and the numbers are
1985, -892.5, 1092.5, 200
To find the value of x in the given Fibonacci-type sequence, we can use the property of Fibonacci numbers.
In a Fibonacci sequence, each number (after the first two) is the sum of the two preceding numbers.
So, let's start with the given terms: 1985, x, y, 200.
We know that 1985 and x are consecutive terms, which means that x is the sum of the two preceding terms: 1985 and y.
Similarly, y is the sum of the preceding terms: x and 200.
Using this information, we can form two equations:
1) x = 1985 + y
2) y = x + 200
Now, we can solve these equations simultaneously to find the value of x.
Substituting the value of y from equation 2 into equation 1, we get:
x = 1985 + (x + 200)
x = 1985 + x + 200
x - x = 2185
0x = 2185
x = 2185
Therefore, x equals 2185.