Posted by **Anonymous** on Thursday, August 7, 2014 at 3:22pm.

HNO3 used as a reagent has a specific gravity of 1.42 g/ mL and contains 70% by strength HNO3. Calculate:

Volume of acid that contains 60 g pure acid?

Volume of water required to make 1 molar solution from 2 mL concentrated HNO3?

- Chemistry -
**bobpursley**, Thursday, August 7, 2014 at 3:39pm
60g/1.42g/ml= 42.25ml

Molarity concentrated sol= .060/63*1/42.25= 2.25

so you want to dilute it 2.25/1 times, which means one part concentrated HNO#, 1.25 part water.

One part is 2ml, so 1.25 part water is 2.50ml

- Chemistry -
**DrBob222**, Thursday, August 7, 2014 at 4:01pm
I have interpreted the problem differently from Bob Pursley so my answers differ.

First, the pure acid is what molarity?

1.42 x 1000 x 0.70 x (1/63) = 15.8M

Then use c1v1 = c2v2

15.8M x 2 mL = 1M x v2

v2 = about 15.8 x 2/1 = about 31.6 mL = total volume v2 which means you add about 31.6-2 = about 29.6 mL H2O

Then to obtain 60 g pure HNO3 you will want 1.42 g/mL x ?mL x 0.70 = 60 and solve for ? mL. I obtained something like 60g of the pure acid.

- Chemistry -
**john**, Friday, September 9, 2016 at 9:39pm
60g/1.42g/ml= 42.25ml

Molarity concentrated sol= .060/63*1/42.25= 2.25

so you want to dilute it 2.25/1 times, which means one part concentrated HNO#, 1.25 part water.

One part is 2ml, so 1.25 part water is 2.50ml

First, the pure acid is what molarity?

1.42 x 1000 x 0.70 x (1/63) = 15.8M

Then use c1v1 = c2v2

15.8M x 2 mL = 1M x v2

v2 = about 15.8 x 2/1 = about 31.6 mL = total volume v2 which means you add about 31.6-2 = about 29.6 mL H2O

Then to obtain 60 g pure HNO3 you will want 1.42 g/mL x ?mL x 0.70 = 60 and solve for ? mL. I obtained something like 60g of the pure acid.

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