A mixture contains n2o4 and No2 in the ratio 2:1 by volume what is the vapour density of the mixture.Pls answer the question i have been on the question for 2 hrs by now tried solving using mole fraction ideal gas equation an using the formula molar mass /2 but still couldn't get the answer ans as is written is 38.3 pls tell how .explain in detail may be

Molar mass of N2O4 =92

Vapour density= 46(92/2)
Molar mass of NO2=46
Vapour density=23(46/2)
Given ratio is 2:1
So vapour density of mixture is
2×46+23/3 =38.33
We devide it by 3 because
Sum of ratio is 3 .

I think the trouble you are having is knowing what vapor density is. vapor density = molar mass gas/molar mass H2.

vapor density N2O4 = molar mass N2O4/molar mass H2 = 92.011/2.016 = 45.64
vapor density NO2 = molar mass NO2/molar mass H2 = 46.0055/2.016 = 22.82

The ratio is 2:1 in favor N2O4; therefore,

v.d. N2O4 x 2 = 91.28
+ v.d. NO2 x 1 = 22.82
sum is 114.1
average is 114.1/3 = 38.033 which rounds to 38.03.

jhakaaaaas

To determine the vapor density of the mixture, we need to calculate the average molar mass of the molecules in the mixture.

1. Determine the molar mass of each component:
- N2O4 (Dinitrogen Tetroxide): The molar mass of N2O4 is 46.01 g/mol.
- NO2 (Nitrogen Dioxide): The molar mass of NO2 is 46.01 g/mol.

2. Determine the ratio of the volumes of the two components:
The mixture is in a volume ratio of 2:1, which means for every two volumes of N2O4, there is one volume of NO2.

3. Calculate the total molar mass of the mixture (TM):
TM = (2 moles of N2O4) + (1 mole of NO2)
TM = (2 * 46.01 g/mol) + (1 * 46.01 g/mol)
TM = 138.03 g/mol

4. Calculate the number of moles of the mixture (n):
We need the number of moles of N2O4 and the number of moles of NO2, which we can find using the ratio of their volumes.
Let's assume we have two volumes (2V) of N2O4 and one volume (V) of NO2.
So, the total volume of the mixture is 3 volumes (2V + V).
According to the ideal gas law, V/T = constant; therefore, the number of moles of a gas is directly proportional to its volume when temperature and pressure are constant.
Since the ratio of the volumes is 2:1, the ratio of the moles is also 2:1. Let's assume n1 is the number of moles of N2O4 and n2 is the number of moles of NO2. Then:
n1/n2 = (2V)/(V) = 2/1
n1/n2 = 2

To find the actual values of n1 and n2, we can assign arbitrary values to either n1 or n2. Let's assume n2 = 1 mol, which means n1 = 2 mol.

5. Calculate the total mass of the mixture:
Total mass of the mixture = (mass of N2O4) + (mass of NO2)
Total mass of the mixture = (n1 * molar mass of N2O4) + (n2 * molar mass of NO2)
Total mass of the mixture = (2 * 46.01 g) + (1 * 46.01 g)
Total mass of the mixture = 138.03 g

6. Calculate the molar mass of the mixture (MM):
MM = (total mass of the mixture) / (number of moles of the mixture)
MM = 138.03 g / 3 mol
MM = 46.01 g/mol

7. Calculate the vapor density of the mixture:
Vapor density = (molar mass of the mixture) / 2
Vapor density = 46.01 g/mol / 2
Vapor density = 23.005 g/mol

Hence, the vapor density of the given mixture is 23.005 g/mol.