Thursday

February 26, 2015

February 26, 2015

Posted by **Patrick** on Thursday, August 7, 2014 at 11:34am.

- statistics -
**PsyDAG**, Thursday, August 7, 2014 at 2:07pmZ = (score-mean)/SEm

SEm = SD/√n

Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportion/probability of the Z score.

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