posted by karl on .
A box of 200kN is placed on a smooth inclined plane 28° with the horizontal. To prevent the box from sliding down the plane, a rope is tied to it and fastened to a peg on the top of the incline as shown. Determine the pull on the string assuming that the rope is held parallel to the plane. (Hint: the pull in the string must be equal to the component of the weight of the box parallel to the palne)
m*g = 200,000N.
Fp = mg*sin A = 200,000*sin28 = 98,894 N
= Force parallel with the incline = The
pull on the rope.