8-3 greater than 4-2y
8-3 greater than 4-2y
5 > 4 - 2y
1 > -2y
- 1/2 > y
5 > 4 - 2 y
1 > -2 y
divide by -2, when you multiply or divide by a negative, change direction of arrow
- 1/2 < y
so
y > -1/2
now check that by picking some y which is greater than (to the right of on number line) -1/2
like maybe -1/4
8 - 3 > 4 - 2(-1/4) ????
5 > 4 + 1/2 yes
Ms Sue, negative divide changes arrow direction.
Oops! Thanks, Damon!
:-)
To determine if 8-3 is greater than 4-2y, we can start by simplifying both sides of the inequality.
8 - 3:
Since subtraction is associative, we can subtract 3 from 8:
8 - 3 = 5.
4 - 2y:
Here, we have a variable, y. The value of y is unknown, so we need to leave it as it is.
Therefore, 4 - 2y stays as 4 - 2y.
Now we have the new inequality:
5 > 4 - 2y
Next, we can further simplify the inequality by combining like terms.
5 is the same as 4 + 1, so the inequality becomes:
4 + 1 > 4 - 2y.
Simplifying the equation gives us:
5 > 4 - 2y.
We can now solve for y by isolating y on one side of the inequality.
First, let's bring the term with y to the left side:
5 + 2y > 4.
Next, let's isolate the term with y by subtracting 4 from both sides of the inequality:
5 + 2y - 4 > 4 - 4.
Simplifying the equation gives us:
2y + 1 > 0.
Now, subtract 1 from both sides of the inequality to isolate y:
2y + 1 - 1 > 0 - 1.
Simplifying the equation further gives us:
2y > -1.
Lastly, divide both sides of the inequality by 2 to solve for y:
(2y) / 2 > (-1) / 2.
Simplifying the equation finally gives us the solution:
y > -1/2.
So, the final answer is y is greater than -1/2.