multiply the polynomial (x-1)(2x squared-x-3)

Did I not just do that ?

again:

http://www.jiskha.com/display.cgi?id=1407198511

x(2x squared-x-3)+ 1(2x squared-x-3)

x.2x squared+x.x+x.3+2x squared-x-3
2x cube+x squared+3x+2x squared-x-3
5x squared-2x squared-3x

Your notation is extremely awkward. We normally write x to a power as

x^power like x^3 is x cubed
Now I will do it your way but you have errors starting with the sign in the first line
x(2x squared-x-3)+ 1(2x squared-x-3)
should be
x(2x squared-x-3) - 1(2x squared-x-3)
then
x*2xsquared -x*x -3x -2xsquared +x+3
or
2 x cubed - 3 x squared -2 x +3

To multiply the given polynomial (x - 1)(2x^2 - x - 3), you can use the distributive property.

First, multiply each term in the first polynomial (x - 1) with each term in the second polynomial (2x^2 - x - 3):

(x - 1) * 2x^2 = 2x^3 - x^2
(x - 1) * (-x) = -x^2 + x
(x - 1) * (-3) = -3x + 3

Next, combine the like terms:

2x^3 - x^2 - x^2 + x - 3x + 3

Finally, simplify the expression:

2x^3 - 2x^2 - 2x + 3

Therefore, the result of multiplying the given polynomials is 2x^3 - 2x^2 - 2x + 3.