KNO3+H2SO4=K2SO4+HNO
what mass of sulfuric acid in gram is needed for 2 moles of potassium nitrate?
how many moles of mitric acid will be produced from 5 moles of sulfuric acid?
what mass in gram of potassium sulfate will be produced from 5 moles of potassium sulfate?
The corrected equation is as follows and I've balanced it as well:
2KNO3 + H2SO4 = K2SO4 + 2HNO3
mols H2SO4 needed = 2 mols KNO3 x (1 mol H2SO4/2 mol KNO3) = 2*1/2 = 1 mol H2SO4 needed.
g H2SO4 = mols H2SO4 x molar mass H2SO4.
b.
5 mols H2SO4 x (2 mol HNO3/1 mol H2SO4 = 5 x 2 = ?
c.
I don't think you posted the right question for c. I suspect you exchanged some things. I think you probably wanted to know grams K2SO4 produced by 5 mol KNO3.
That's 5 mol KNO3 x (1 mol K2SO4/2 mol KNO3) = ?
Then grams = mols x molar mass.
To find the mass of sulfuric acid needed for 2 moles of potassium nitrate, we first need to determine the molar ratio between potassium nitrate (KNO3) and sulfuric acid (H2SO4) based on the balanced equation:
KNO3 + H2SO4 → K2SO4 + HNO3
From the balanced equation, we can see that the ratio between KNO3 and H2SO4 is 1:1. This means that for every 1 mole of KNO3, we need 1 mole of H2SO4.
Therefore, if we have 2 moles of KNO3, we would also need 2 moles of H2SO4.
Next, we need to convert moles of H2SO4 to grams. To do this, we need to know the molar mass of H2SO4, which is 98.09 g/mol.
So, to find the mass of sulfuric acid needed for 2 moles of potassium nitrate:
Mass of H2SO4 = moles of H2SO4 × molar mass of H2SO4
= 2 moles × 98.09 g/mol
= 196.18 g
Therefore, 196.18 grams of sulfuric acid is needed for 2 moles of potassium nitrate.
Moving on to the second question:
To find the number of moles of nitric acid (HNO3) produced from 5 moles of sulfuric acid, we need to determine the molar ratio between H2SO4 and HNO3.
From the balanced equation:
KNO3 + H2SO4 → K2SO4 + HNO3
We can see that the ratio between H2SO4 and HNO3 is 1:1. This means that for every 1 mole of H2SO4, we will also produce 1 mole of HNO3.
Therefore, if we start with 5 moles of H2SO4, we will produce 5 moles of HNO3.
Finally, for the last question:
To find the mass of potassium sulfate (K2SO4) produced from 5 moles of potassium sulfate, we need to know the molar mass of K2SO4, which is 174.26 g/mol.
So, to find the mass of potassium sulfate:
Mass of K2SO4 = moles of K2SO4 × molar mass of K2SO4
= 5 moles × 174.26 g/mol
= 871.3 g
Therefore, 871.3 grams of potassium sulfate will be produced from 5 moles of potassium sulfate.