The time required for a car to reach 28.5 m/s from rest, accelerating at 3.70 m/s2 is __________ .
v = Vi + a t
28.5 = 0 + 3.70 t
7.70s
To find the time required for a car to reach a certain speed from rest while accelerating, we can use the formula of motion:
v = u + at
Where:
v = final velocity (28.5 m/s)
u = initial velocity (0 m/s, since the car is at rest)
a = acceleration (3.70 m/s^2)
t = time.
Rearranging the formula, we have:
t = (v - u) / a
Substituting the given values, we have:
t = (28.5 m/s - 0 m/s) / 3.70 m/s^2
Now, let's calculate:
t = 28.5 m/s / 3.70 m/s^2
t = 7.7027 s
Therefore, the time required for the car to reach 28.5 m/s from rest, while accelerating at 3.70 m/s^2, is approximately 7.70 seconds.