An aircraft on its take-off run has a steady acceleration of 3.0 m/s2. It's velocity after 10 seconds will be
assume start from rest
v = Vi + a t
v = 0 + 3 * 10
which is 30 m/s
To find the velocity of the aircraft after 10 seconds, we can use the equation of motion:
v = u + at
Where:
v = final velocity
u = initial velocity (which is usually assumed to be zero in this context, as it is the take-off run)
a = acceleration
t = time
Given that the acceleration (a) is 3.0 m/s^2 and the time (t) is 10 seconds, we can substitute these values into the equation:
v = 0 + (3.0 m/s^2) * 10 s
v = 0 + 30 m/s
Therefore, the velocity of the aircraft after 10 seconds will be 30 m/s.