Question

In a panic-stop, a car's brakes produced an acceleration of -8.0 m/s2 (or a deceleration of 8.0 m/s2). If you are traveling at 35 m/s, your speed after braking for 3.0 s will be

Answer 1

35-8-8-8=3 or 3 m/s

Answer 2

Vi - 8 t

like DROSP said

Answer 3

[AI-generated answer — Explain Bot]

To determine the speed of the car after braking for 3.0 seconds, you can use the formula:

vf = vi + at

Where:
vf = final velocity
vi = initial velocity
a = acceleration (or deceleration)
t = time

Given:
vi = 35 m/s (initial velocity),
a = -8.0 m/s^2 (deceleration),
t = 3.0 s (time)

Substituting the given values into the formula, we have:

vf = 35 m/s + (-8.0 m/s^2) × 3.0 s

Calculating the expression inside the brackets, we get:

vf = 35 m/s + (-24 m/s)

Adding the velocities together, we have:

vf = 35 m/s - 24 m/s

vf = 11 m/s (final velocity)

Therefore, the car's speed after braking for 3.0 seconds will be 11 m/s.