A hockey puck with a mass of 0.200 kg travels with a speed of 49.6 m/s during a slap shot. The puck's kinetic energy is
KE = .5 x (m x v^2)
so
KE = .5 x (.2 * (49.6)^2)
To find the kinetic energy of the hockey puck, you can use the formula:
Kinetic Energy = (1/2) * mass * velocity^2
Given that the mass of the hockey puck is 0.200 kg and the speed is 49.6 m/s, we can substitute these values into the formula:
Kinetic Energy = (1/2) * 0.200 kg * (49.6 m/s)^2
First, let's square the velocity:
(49.6 m/s)^2 = 49.6 * 49.6 = 2,457.6 m^2/s^2
Now, we can substitute this value back into the equation:
Kinetic Energy = (1/2) * 0.200 kg * 2,457.6 m^2/s^2
Next, let's calculate the product of the mass and the squared velocity:
(1/2) * 0.200 kg * 2,457.6 m^2/s^2 = 0.100 kg * 2,457.6 m^2/s^2
Finally, multiply the values together to find the kinetic energy:
Kinetic Energy = 0.100 kg * 2,457.6 m^2/s^2 = 245.76 J
Therefore, the kinetic energy of the hockey puck during the slap shot is 245.76 Joules.