Posted by **Aly** on Wednesday, July 30, 2014 at 8:17pm.

What is the domain of the following function?

f(x) = √ -x + 2 - 1

- Algebra1 -
**Reiny**, Wednesday, July 30, 2014 at 9:07pm
You will have to use brackets to show where the square root ends

I suspect it is f(x) = √(-x+2) - 1 , or else why not combine the +2-1 ?

then the number under the square root must not be negative, that is ...

-x + 2 ≥ 0

-x ≥ -2

x ≤ 2

- Algebra1 -
**Steve**, Wednesday, July 30, 2014 at 9:07pm
depends. How much of all that is under the radical sign?

Once you specify that, just remember that the domain of √u is u>=0.

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