Algebra1
posted by Aly on .
What is the domain of the following function?
f(x) = √ x + 2  1

You will have to use brackets to show where the square root ends
I suspect it is f(x) = √(x+2)  1 , or else why not combine the +21 ?
then the number under the square root must not be negative, that is ...
x + 2 ≥ 0
x ≥ 2
x ≤ 2 
depends. How much of all that is under the radical sign?
Once you specify that, just remember that the domain of √u is u>=0.