February 21, 2017

Homework Help: Chemistry

Posted by Queen on Wednesday, July 30, 2014 at 7:59pm.

In order to make 500.0mL of a 1.835 M MgCl2 solution, then _______g of MgCl2 is needed.

Moles of MgCl2= (1.835M)(0.5L)=0.9175mol
Molecular Weight of MgCl2= 95.211 g/mol

(0.9175mol MgCl2)(95.211 g/mol)=
87.36g of MgCl2

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