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March 25, 2017

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a wheel rotating at 1800 rpm slows down uniformly to 1200 rpm in 2.0 sec. calculate a)the angular acceleration (revs/s^2) of the motor. and b) the number of revolutions it makes in this time.

  • PHYSICS - ,

    number of revolutions:

    d=avgspeed*time=1500rpm*2/60 min

    acceleration:
    wf=wi+at
    a= (wf-wi)/t=600rpm*2PIrad/rev*1m/60sec*1/2sec

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