Post a New Question


posted by .

a 60g golf ball leaves the face of the club with a velocity of 75m/s. if the club exerted an average force of 3.0x10to the 4th N, what was the time of impact between the club and the ball?

  • physics -

    F = m*a
    a = F/m = 3.0*10^4/0.06 = 5*10^5 m/s^2.

    a = (V-Vo)/t = 5*10^5 m/s^2
    (75-0)/t = 5*10^5
    5*10^5t = 75
    t = 1.5*10^-4 s.

Answer This Question

First Name:
School Subject:

Related Questions

More Related Questions

Post a New Question