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how would you prepare 250 mL of 0.69M Al2(SO4)3 solution from a 2.0M Al2(SO4)3 stock solution?

  • Chemistry -

    Ah Ha! So you're posting the problem right. And you see there is a difference in m and M.

    How many mols do you want? That's M x L = mols.
    Then mols = grams/molar mass. You know molar mass and mols, solve for grams.

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