An object carries a charge of -6.9 µC, while another carries a charge of -2.0 µC. How many electrons must be transferred from the first to the second object so that both objects have the same charge?

the difference is 4.9µC. So, move half that, or 2.45µC. Now just convert that to no. electrons.

To find out the number of electrons transferred, we first need to determine the charge on one electron.

The charge on one electron is given by the elementary charge, which is approximately -1.6 × 10^-19 coulombs (C).

Now, let's calculate the number of electrons transferred.

1. Begin by finding the charge difference between the two objects.
q1 = -6.9 µC
q2 = -2.0 µC

Δq = q2 - q1
= (-2.0 µC) - (-6.9 µC)
= (-2.0 µC) + (6.9 µC)
= 4.9 µC

2. Convert the charge difference into coulombs.
1 µC = 1 × 10^-6 C

Δq (in C) = 4.9 µC × (1 × 10^-6 C/µC)
= 4.9 × 10^-6 C

3. Determine the number of electrons transferred.
The elementary charge is -1.6 × 10^-19 C per electron.

Number of electrons transferred = Δq / elementary charge
= (4.9 × 10^-6 C) / (-1.6 × 10^-19 C/electron)
= -3.06 × 10^13 electrons (rounding to two decimal places)

Therefore, approximately 3.06 × 10^13 electrons must be transferred from the first object to the second object so that both objects have the same charge.